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DOS: create filename based on date?

Last answer on Jul 30, 2009 7:11:51 pm BST whitedog1, on Jul 24, 2009 1:33:11 pm BST 
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Hello,

I need to be able to automatically generate a DOS .txt filename that is the 'date' of when it is created.

Any ideas? My DOS is rather rusty and have run out of ideas.

Configuration: Windows XP Internet Explorer 7.0  (XP Dos)

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1

mildman, on Jul 24, 2009 2:09:07 pm BST

Try this:

copy con %DATE%.txt

the press Ctrl-Z.

This will create a zero-length file named 24-Jul-2009.txt (or whatever).

   
Reply to mildman

2

mildman, on Jul 24, 2009 2:12:25 pm BST

Sorry, that won't work from a batch file! If you don't mind what is in the file then this will work:

echo >%DATE%.txt

And if a zero-length file is important to you then create one manually as described before, then use:

copy yourZeroLengthFile %DATE%.txt

   
Reply to mildman

3

sandbeha, on Jul 30, 2009 7:11:41 pm BST

You might try something like this...


set filea=MyBigFile%date:~10%%date:~4,2%%date:~7,2%%time:~0,2%%t­ime:~3,2%.sav
copy MyData.dat %filea%

Since the date is Thu 07/30/2009 and the time is 14:07:00.00,
For today this would give a file named
MyBigFile200907301407.sav

good luck

   
Reply to sandbeha

4

 sandbeha, on Jul 30, 2009 7:11:51 pm BST

You might try something like this...


set filea=MyBigFile%date:~10%%date:~4,2%%date:~7,2%%time:~0,2%%t­ime:~3,2%.sav
copy MyData.dat %filea%

Since the date is Thu 07/30/2009 and the time is 14:07:00.00,
For today this would give a file named
MyBigFile200907301407.sav

good luck

   
Reply to sandbeha
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